2x^2+8=x^2+40

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Solution for 2x^2+8=x^2+40 equation:


Simplifying
2x2 + 8 = x2 + 40

Reorder the terms:
8 + 2x2 = x2 + 40

Reorder the terms:
8 + 2x2 = 40 + x2

Solving
8 + 2x2 = 40 + x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x2' to each side of the equation.
8 + 2x2 + -1x2 = 40 + x2 + -1x2

Combine like terms: 2x2 + -1x2 = 1x2
8 + 1x2 = 40 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
8 + 1x2 = 40 + 0
8 + 1x2 = 40

Add '-8' to each side of the equation.
8 + -8 + 1x2 = 40 + -8

Combine like terms: 8 + -8 = 0
0 + 1x2 = 40 + -8
1x2 = 40 + -8

Combine like terms: 40 + -8 = 32
1x2 = 32

Divide each side by '1'.
x2 = 32

Simplifying
x2 = 32

Take the square root of each side:
x = {-5.656854249, 5.656854249}

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